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5y^2+21y+22=0
a = 5; b = 21; c = +22;
Δ = b2-4ac
Δ = 212-4·5·22
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-1}{2*5}=\frac{-22}{10} =-2+1/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+1}{2*5}=\frac{-20}{10} =-2 $
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